Fonksiyonlar

x=0 \ \rightarrow \ f(2)=3+f(5) \\ x=3 \ \rightarrow \ f(5)=3+f(8) \\ x=6 \ \rightarrow \ f(8)=3+f(11) \\ \vdots \\\\ x=45 \ \rightarrow \ f(47)=3+f(50) \\ + -------------- \\f(2) =3. \frac{45-0}{3} + f(50) \\\\ f(50)=-38. \\ \therefore